A car is travelling at 20m/s along a road, a child runs out inti the road 15m ahead and the car driver steps upon the break paddle. What must be the cars acceleration if the car is to stop just before it reaches the child
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v = 15m
u = 20m/s
t = s
a = v - u/t
a = 15m - 20m / s X s
a = -5m/s²
u = 20m/s
t = s
a = v - u/t
a = 15m - 20m / s X s
a = -5m/s²
Anirudh11q:
v = final velocity
u = initial velocity
then
1eqn v = u + at so a = v-u/t
v = 15
u = 20
t = 1s
15 - 20 = -5
s x s = s^2
why are we doing s×s=s^2
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