Question

a car is travelling at 36 km per hour speed up to 72 km per hour in 5 second what is the acceleration.​

Answer 1

Question :-

A car traveling at 36 km/h speeds up to 72 km/h in 5 seconds. What is the acceleration of the Car?​

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Solution :-

Given,

Initial Velocity, u = 36 km/h ;

Final Velocity, v = 72 km/h ;

Time, t = 5 Seconds

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Converting all the Quantities in the same Unit, we have -

Initial Velocity of the Car, u = $\mathtt {36\: kmh^{-1} \times \dfrac{5}{18}} = \bf 10\: ms^{-1}$

Final Velocity of the Car, v = $\mathtt {72\: kmh^{-1} \times \dfrac{5}{18}} = \bf 20\: ms^{-1}$

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We know,

$\boxed {\mathtt {Acceleration, a = \dfrac{v - u}{t}}}$

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Substituting the given Values of u, v and t in the above Equation, we get -

$\begin {aligned} \bold {Acceleration, a} &= \dfrac{(20\: ms^{-1} - 10\: ms^{-1})}{5\: s}\\\\&\Rightarrow \dfrac{10\: ms^{-1}}{5\: s}\\\\\therefore \ \bold a &= \underline {\boxed {\bf 2\: ms^{-2}}}\ \star \end {aligned}$

Hence, the Acceleration of the Car is $\underline {\underline {\bf 2\: ms^{-2}}}$

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Additional Information :-

$\bullet$ The Speed of an Object is the Distance covered per unit time, and Velocity is the Displacement per unit time.

Speed and Velocity have the same units, that is, $ms^{-1}$ or m/s

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$\bullet$ The Acceleration of an Object is the change in Velocity per unit time. That is,

$\mathrm {Acceleration = \dfrac{Change\: in\: Velocity}{Time\: Taken}}$