A car is travelling at 54km/h.If breaks are applied so as to produce uniform retardation of 5m/s square. Calculate the time taken by it to stop.
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speed = 54 x 5/ 18 = 15 m/s
v-u= at
t= 15/ 5
t= 3 sec
v-u= at
t= 15/ 5
t= 3 sec
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