Question

a car is travelling at 72km/h breaks are applied and the car reduce its speed to the 36km/h after distance of 10 m find the retardation​

Answer 1

Answer:

here is your answer.........

Answer 2

Answer:

a=-15m/s^2

Explanation:

u=72 k/h = 72×5/18=20m/s

v=36k/h = 10 ×5/18 = 10m/s

s=10m

a =?

FROM FORMULA=

2as=v^2 - u^2

2×a×10=10^2 - 20^2

20a = 100-400

20a= -300

a= -300/20

a= -15m/s

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