Question

A car is travelling at a speed of 21 m/s1. It accelerates at an average rate of 3 m/s2 for a time of 4 seconds. Find the distance it travels during the 4 seconds?

Answer 1

Answer:

[ s = distance , u = initial velocity , t = time , a = acceleration ]

s = ut + 1/2 at^2. ( equation : 2nd law of motion )

s = 21m/s * 4s + 1/2*3m/s^2*(4s)^2

s = 84m + 1/2 * 3m/s^2* 16s^2

s = 84m + 12m

s = 96m

hope it helps you

Answer 2

Answer: 108 m

Explanation:

S=ut+ 1/2 *at^2

S= 21*4 + 1/2 * 3* 4^2

S= 84+ 1/2* 3* 16

S= 84+ 1/2 *48

S= 84+24

S= 108 meters