A car is travelling at a speed of 36 km/hr. The driver applies brakes and retards the car uniformly. The car is stopped in 5s. Find the distance travelled before it stops.
Answers
Answered by
121
v=u+at
v=0
u=36km/hr=10m/s
0= 10+5a
a=-2m/s^2
S=ut+1/2at^2
=50-25
S=25m
v=0
u=36km/hr=10m/s
0= 10+5a
a=-2m/s^2
S=ut+1/2at^2
=50-25
S=25m
Answered by
93
in this situation
u = 36 km per hour = 10 m per second
v = 0 as driver apply brakes
t = 5 seconds
a = v - u divided by t
so a = -2 m per second (-due to retardation)
s =ut + half a(t)^2
s = 50 + (-25)
s = 25 metres
u = 36 km per hour = 10 m per second
v = 0 as driver apply brakes
t = 5 seconds
a = v - u divided by t
so a = -2 m per second (-due to retardation)
s =ut + half a(t)^2
s = 50 + (-25)
s = 25 metres
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