A car is travelling at a speed of 6 m/s. Brakes are applied so as to produce a uniform acceleration of – 1 m/s2. Find how far the car will go before it is brought to rest?
Answers
Answer:
18m
Explanation:
U=6m/s
V=0m/s......( bcs brakes are applied)
a= -1m/s^2
we have to find s
(s =displacement)
by formula v^2-u^2=2as
0^2-6^2=2(-1)(s)
0-36=-2s
-36= -2s
-36/-2 = s
18 m= s
Explanation:
Given that,
Acceleration a=−0.5m/s
2
Speed v=90km/h=25m/s
Using equation of motion,
v=u+at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Finally train will be rest so, final velocity,v=0
0=25−0.5t
25=0.5t
t=
0.5
25
t=50 sec
Again, using equation of motion,
S=ut+
2
1
at
2
Where, s = distance
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Where S is distance travelled before stop
s=25×50−
2
1
×0.5×(50)
2
s=625 m
So, the train will go before it is brought to rest is 625 m.