Question

A car is travelling at a speed of 72km/h, the brakes are applied so as to produce a uniform acceleration of -1m/s2. Find the distance it travels after applying brakes so that it completely stops?

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Answer 1

Hii its tom85

v=0

u = 72km/hr = 20m/s

v^2 =u ^2 -2as

s = u^2/2a

s = -400/2

s = -200m

s= 200 m in opposite directions

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hope it may helps you

Answer 2

Answer:

Explanation:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time.

s = Distance

Given :-

Final speed  of a car, v = 0 (Because car stops by applying breaks)

Initial speed  of a car, u = 72 m/s = 72 × 5/18 = 20 m/s

Acceleration by the car, a = -1 m/s²

To Find :-

Distance Traveled

Formula to be used :-

Third equation of motion that is v²- u² = 2as

Solution :-

⇒ v²- u² = 2as

⇒ 0²-(20)² = 2×-1×s

⇒ -400 = -2s

⇒ s = 200 m

Hence, The car will travel a distance of 200m before coming to rest.