Question

A car is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of – 0.5 m/s2. Find how far the car will go before it is brought to rest?​

Answer 1

Given that,

Given that,Acceleration, a=−0.5m/s²

Speed, v=90km/h=25m/s

Using equation of motion,

v=u+at

Where, v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation.

Finally car will be rest so, final velocity,v=0

0=25-0.5t

25=0.5t

25=0.5t

t= 0.5/25

25t=50 sec.

Again, using equation of motion,

S=ut+1/2 at²

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stops

→25×50−1/2×0.5×(50)²

s=625 m

So, the car will go before it is brought to rest is 625 m.

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