Question

A car is travelling at a speed of 90km/h . Brakes are applied so as to produce a uniform acceleration of -0.5m/s .Find how far the car will go before it is brought to rest ?

Answer 1

Answer:

With linear deceleration from 90-0, the distance would be exactly half what it would have travelled at 90km/hr, which is (on average) 45km/hr for 10 seconds.

10 sec. divided by 3600 sec/hr multiplied by 45,000 meters = 125 meters.

Explanation:

Answer 2

heyo this is a mechanics Questions

can be solved by applying formula -

${v}^{2} = {u}^{2} + 2as$

90 km/hr = 90 x 5/18 = 25 m/s

$0 = {25}^{2} - 2 \times 0.5s$

by solving we get

s = 625m