Question

A car is travelling at a speed of 90km/h. Brakes are applied so as to produce a uniform acceleration of -0.5m/s2. Find how far the car will go before it is brought to rest. *

a)8100m

b)900m

c)625m

d)620m

​

Answer 1

Answer:

hnhnh

Explanation:

Answer 2

Explanation:

Acceleration a=−0.5m/s2

Speed v=90km/h=25m/s

Using equation of motion, 

v=u+at

Where, 

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

0=25−0.5t

25=0.5t

t=0.525

t=50 sec

Again, using equation of motion, 

S=ut+21at2

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50−21×0.5×(50)2

s=625 m