Question

A car is travelling at a steady velocity of 28 m/s. It accelerates for 6 seconds to overtake a van. Its new velocity is 32.5 m/s. Calculate the acceleration of the car.

Answer 1

Answer:

acceleration= 2.25m/s²

acceleration=final velocity (v) - initial velocity (u)÷ time

that is, a=v-u/t

a=?, v=32.5m/s, u= 28m/s, and t= 6s

a=32.5-28/6

a=4.5/6

a= 2.25m/s²

Answer 2

Answer:

Explanation

V=u+at

where,

v = final velocity of the car = 32.5 m/s

u = initial velocity of the car = 28 m/s

a = acceleration of the car = ?

t = time taken = 6 sec

Putting values in above equation, we get:

32.5=28×a×6

32.5=a×168

0.193 m/s2

Hence, the acceleration of the car is 0.193 m/s2