a car is travelling at a velocity of 36km/h.if its velocity increases to 72 km/h in 10 seconds.find the acceleration of the car
Answers
we know that , Acceleration = change in velocity / time taken
But here the unit of time is given in secs. so,either we have to convert the velocity into m/s or time in hrs.
we know that , 1km = 1000 m & 1hr = 3600 secs.
1km/hr = 1000/3600 m/s = 5/18 m/s ( cancelling 1000/3600,we get 5/18.If you want to convert km/h into m/s,just multiply with 5/18.If you want to convert m/s into km/h then just multiply the value with 18/5 , Its time saving hack! )
so,
Initial Velocity(u) = 36 km/h = 36 x 1000/3600 m/s = 10 m/s
Final Velocity(v) = 72 km/h = 72 x 1000/3600 m/s = 20 m/s
Time taken(t) = 10 secs.
Applying the Basic acceleration formula,
Acceleration(a) = change in velocity (v-u) / t
=> a = v-u / t
=> a = (20-10) / 10 m / sec ^2
=> a = 10 / 10 m / sec^2
=> a = 1 m / sec^2
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