a car is travelling at a velocityof 10.8 km/hr and attains a velocity 54km/hr in 6sec what it's acceleration
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Answer:
7.2km/hr^2
Explanation:
u =10.8km/hr
v=54km/hr
t=6sec
a=?
from
v=u+at
54=10.8+6a
54-10.8=6a
43.2=6a
43.2÷6=a
7.2=a
hence acceleration is 7.2km/hr^2
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