a car is travelling at speed of 20km/h.it acquires the velocity of 30km/h in 5s. calculate the acceleration and distance covered by the car.(using equation of motion)
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hey dear
here is your answer
given data :
initial velocity (u) = 20 km/hr or 5.55 m/s
final velocity (v) = 30 km/hr or 8.33 m/s
time taken (t) = 5 seconds
to find : acceleration & distance travelled
here we go
solution : for acceleration
by using 1st equation of motion
v = u+at
8.33 = 5.55+5a
a = 0.556 m/s²
solution : for distance travelled
by using thiurd equation of motion
v² = u²+2as
(8.33)² = (5.55)²+2*0.556*s
69.3 = 30.8+1.112s
1.112s = 38.9
s = 34.98 meter or ( approximately 35 meter )
hope it helps :)
here is your answer
given data :
initial velocity (u) = 20 km/hr or 5.55 m/s
final velocity (v) = 30 km/hr or 8.33 m/s
time taken (t) = 5 seconds
to find : acceleration & distance travelled
here we go
solution : for acceleration
by using 1st equation of motion
v = u+at
8.33 = 5.55+5a
a = 0.556 m/s²
solution : for distance travelled
by using thiurd equation of motion
v² = u²+2as
(8.33)² = (5.55)²+2*0.556*s
69.3 = 30.8+1.112s
1.112s = 38.9
s = 34.98 meter or ( approximately 35 meter )
hope it helps :)
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