Question

a car is travelling due west at 20.0m/s . find the velocity of the car after 3 s if uts acceleration is 1.0m/s² due east. Assume the acceleration remains constant.
a.17.0m/s west
b.17.0m/s east
c.23.0m/s west
d.23.0m/s east

Answer 1

Explanation:

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Answer 2

Answer:

The final velocity of the car is 17m/s west.

Explanation:

Given that,

a car is traveling due west at 20.0m/s and we are required to find the velocity of the car after 3s if its acceleration is 1.0m/s² due east.

We shall solve this problem using vector algebra.

The initial velocity of the car is $\vec u=-(20)\hat i$

Acceleration of the car is $\vec a=(1\:m/s^2)\vec i$

Time taken is $t=3\:sec$

The final velocity of the car is given by the equation

$\vec v=\vec u+\vec at$

By substituting given values we get

$\vec v=(-20\hat i)+(\hat i)(3)=-17\hat i$

It is in the west direction.

Therefore,

The final velocity of the car is 17m/s west.

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