a car is travelling in a straight line at 25 ms-1. The car brakes for 5.0 s and the speed is reduced uniformly to 15 ms-1. How far does the car travel in this time?
Answers
Answered by
6
Answer:
acceleration= (v-u)/t
=(15-25)/5
= -10/5
=-2m/s^2
v^2=u^2 +2aS
625=225+2*-2*s
400/-4= S
-100m =S
the car travells 100 meters in that time
Explanation:
Answered by
0
Answer:
56.25 Metre
Explanation:
Initial Velocity = 25 m/s
Final Velocity = 15 m/s
Time = 5 s
Therefore,
Retardation = (v-u)/t
=( 15-25 )/5
= -2
= 2
Let d be the distance travelled,
We Know,
v²-u² = 2 aS
=> 15²=2.2.d
=> 225÷4 = d
=> d = 56.25
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