A car is travelling with a speed of 10 m/s decreases its speed to 4 m/s in a time interval of 3 s. then its acceleration is
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solution: given
initial speed(u) = 10m/s
final speed (v) = 4m/s
time interval (t) = 3 sec
acceleration (a) = ?
we know that,
a = final speed-intial speed÷time or v-u/t
putting the values,
a = 4-10/3= -6/3= -2m/s²
minus sign indicate that the speed with time and this minus type of acceleration is also called retardation.
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