A car is travelling with a speed of 36 km/h. The driver applied the brakes and retards
the car uniformly. The car is stopped in 5 sec. Find (i) The acceleration of car and (ii)
Distance before it stops after applying breaks?
Answers
Answered by
11
v=0,u=10m\s,t=5sec
a=v-u\t
a=-10\5
a=-2m\sec
speed=distance\time
10=distance\5
10 into 5=distance
50 meters ans
a=v-u\t
a=-10\5
a=-2m\sec
speed=distance\time
10=distance\5
10 into 5=distance
50 meters ans
sabrina765:
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Answered by
23
Heya mate
here is your answer
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thank u:-)
here is your answer
I hope this will help you....✌️✌️
thank u:-)
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Good answer. Keep it up. :clap:
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