A car is travelling with a speed of 36 km/h. The driver applies brakes and retardes the car uniformly. The car stopped in 5 secs.Find the retardation of the car and distance travelled before and after applying the brakes.
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retardation is negative acceleration so a=v-u/t. and distance=2aS=v square-u square
Answered by
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The distance covered before applying brakes can't be found as the data is inadequate.
HOPE THE ANSWER COULD HELP !!
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mbxkb:
in my question its not clear how much distance was there before brakes :(
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