Question

A car is travelling with a speed of 36km/h. The driver applied the brakes and retarads the uniformly. The car is stopped in 5 sec find The acceleration of car and distance between it stops after applying break​

Answer 1

Explanation:

First convert 36 km/h in m/s=36000/3600

=10 m/s

Here u=10

V=0

t=5

Acceleration =

V=u+at

0=10+a5

-10=5a

a=-10/5a

a=-2

Distance =v2=u2+2as

0=100+2x(-2)+s

0=100+(-4)s

- 100=-4s

S=-100/-4=25

Distance =25