A car is travelling with a speed of 90 km/hr. The driver applied the brakes and retards the car uniformly. The car is stopped in 10 sec. Find (a) The acceleration of car (b) Distance before it stops after applying brakes.
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Answer:
a). v = 0m/s
u = 90m/s
t = 10s
a = ?
v = u + at
a = v - u
t
a = 0 - 90
10
= -90
10
= -9m/ s²
b). s = ut + 1 at²
2
s = 90 × 10 + 1 × -9 × 10²
2
s = 900 + (-450)
s = 450m
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