Question

a car is travelling with the velocity of 20m/s after 30 sec it covers distance of 1200m calculate the accleration of the car and the final velocity of the car

Answer 1

Answer:

Distance after t = 30s

s = 1200 m

v(0) = 20 m/s

From

S= a/2*t² + v(0) *t

we have

1200 m = a/2 * 900s² + 20 m/s * 30s

So we get for the final acceleration

a =( 1200 m - 600 m)/900 s² * 2 = 1,3333 m/s²

Final velocity is then calculated by

v = a* t + v(0) = 1,3333 m/s² * 30s + 20 m/s = 60 m/s

Answer 2

Answer:

Distance after t = 30s

s = 1200 m

v(0) = 20 m/s

From

S= a/2*t² + v(0) *t

we have

1200 m = a/2 * 900s² + 20 m/s * 30s

So we get for the final acceleration

a =( 1200 m - 600 m)/900 s² * 2 = 1,3333 m/s²

Final velocity is then calculated by

v = a* t + v(0) = 1,3333 m/s² * 30s + 20 m/s = 60 m/s