A car is travelling with the velocity of 72 kom h-! If brakes applied
produce uniform retardation of 10 m 52 calculate the time taken by it to stop.
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Answer:
t = 2sec
Explanation:
Retardation (a) = -10m/s²
Velocity (v) = 72km/h => 72×5/18 => 20m/s
Initial velocity (u) = 0
Time (t) = ?
We know ,
★ v = u + at ★
➞ 20 = 0 + -10 × t
➞ 20 = -10t
➞ t = 20/10
➞ t = 2sec
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