Question

a car is travelling with velocity 20 metre per second the driver applies the brakes to stop the car with negative acceleration of 2 metre per second square find out the distance covered by the car before stop ?
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Answer 1

Answer:

Initial velocity, u=20m/s

Final velocity, v=0m/s

Distance, s=50m

Using relation, v

2

=u

2

+2as

0

2

=(20)

2

+2×a×50

0

2

=400+100a

−400=100a

a=

100

−400

=−4m/s

2

The car's deceleration must be 4m/s

2

.