Math, asked by sheetalkaul999, 5 months ago

A car is valued at ₹ 525000 .It depreciates by 20% in the first year and thereafter each year by15% of its value at the beginning of that year . Find its value (i) after 2 (ii) after 3 years.


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Answers

Answered by anshz08
2

Answer:

after 2 years-357000 after 3 yrs-303,450

Answered by vaibhavjayant7
4

Answer:

i) after 2 years :- 357000 , ii) after 3 years :- 303450

Step-by-step explanation:

initial value = 525000

in first year(20% decrement) = 5250000- 20/100 * 5250000

= 5250000 - 105000

= 420000

in 2nd year ( 15% decrement) = 42000 - 15/100 * 42000

= 420000-63000

=357000

in 3rd year ( 15% decrement) = 357000 - 15/100 * 357000

= 357000 - 53550

= 303450

pls mark me the brainliest  :)

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