A car leaves agra at 11 a.m. traveling at 50 km/h. How fast would a second car be travelling if it leaves agra an hour later and over takes the first car at 5 p.m on the same day
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Answered by
1
well first of all distance travel by first car in 1 hour is = 50 km
second car start one hour later means at 12 0' clock
time taken to over take is = 5 hours
speed of first car-spped of second car =distance/ time
50- second car's speed = 50/5
50 - second car = 10
secobd car = 40
second car start one hour later means at 12 0' clock
time taken to over take is = 5 hours
speed of first car-spped of second car =distance/ time
50- second car's speed = 50/5
50 - second car = 10
secobd car = 40
Answered by
3
distance is same for both the car
let distance =s(as 2nd car overtakes the 1st car)
speed =distance/time
therefore
car 1st takes 6 hrs
and car 2nd takes 5hrs
1V×t1=2V×2t (spd of 1stcar=1v. and 2nd car=2V and time respectively)
2V=1V×1t/2t
2V=50×6/5
2V=60km/hrs
let distance =s(as 2nd car overtakes the 1st car)
speed =distance/time
therefore
car 1st takes 6 hrs
and car 2nd takes 5hrs
1V×t1=2V×2t (spd of 1stcar=1v. and 2nd car=2V and time respectively)
2V=1V×1t/2t
2V=50×6/5
2V=60km/hrs
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