A car leaves Agra at 11 a.m travelling at 50 kilometre per hour. how fast would a second car be traveling if it leave Agra aan hour later and overtake the first car at 5 P.M on same day?
Maansichaudhary:
please answer
Answers
Answered by
181
First, we will see time taken by car A = (5pm-11am) = 6 Hours
Speed = 50kmph
Distance covered = (50*6)Km = 300 Km.
Now, In case of car B
Distance covered = 300 Km
Time taken = (6-1) Hours = 5 hours
Speed of the car B will be (300/5) Kmph i.e. 60 Kmph.
Speed = 50kmph
Distance covered = (50*6)Km = 300 Km.
Now, In case of car B
Distance covered = 300 Km
Time taken = (6-1) Hours = 5 hours
Speed of the car B will be (300/5) Kmph i.e. 60 Kmph.
Answered by
3
60 km/h
Step-by-step explanation:
Time taken by first car = 5 p.m - 11 a.m
= 6 hours
Speed = 50 km/h
Distance = Speed × Time
= 50×6
= 300 km/h
Time taken by second car = 6 hours - 1 hour
= 5 hours
Distance = 300 km
Speed = Distance / Time
= 300/5
= 60 km/h
So, Speed of second car is 60 km/h.
Similar questions