Math, asked by Maansichaudhary, 1 year ago

A car leaves Agra at 11 a.m travelling at 50 kilometre per hour. how fast would a second car be traveling if it leave Agra aan hour later and overtake the first car at 5 P.M on same day?


Maansichaudhary: please answer

Answers

Answered by Monu631
181
First, we will see time taken by car A = (5pm-11am) = 6 Hours
Speed = 50kmph
Distance covered = (50*6)Km = 300 Km.
Now, In case of car B
Distance covered = 300 Km
Time taken = (6-1) Hours = 5 hours
Speed of the car B will be (300/5) Kmph i.e. 60 Kmph.
Answered by swetabaliyan5
3

60 km/h

Step-by-step explanation:

Time taken by first car = 5 p.m - 11 a.m

= 6 hours

Speed = 50 km/h

Distance = Speed × Time

= 50×6

= 300 km/h

Time taken by second car = 6 hours - 1 hour

= 5 hours

Distance = 300 km

Speed = Distance / Time

= 300/5

= 60 km/h

So, Speed of second car is 60 km/h.

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