A car leaves Hyderabad at 6:00 am and reaches Vijayawada at10:00am.Another car
leaves Vijayawada at 8:00 am and reaches Hyderabad at 11:20 am
at what time do the two cars cross each other?
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Answer:
at 8.54 they both meet
Step-by-step explanation:
let distance to be travelled is 400 kms
so car A speed=100kms/hr (400/4 hrs)
Car B speed=120km/hr (400/10/3)
11.20 mins can be written as 11+(20/60)= 10/3
so when car B starts, Car A aready travels for 2 hrs at 100 kms/hr so 200 kms travelled
now car B starts at 8 am
then speeds will sum of speed as they are approaching towards each other
S=S1+S2=220kms/hr
distance=200kms but not 400 because , A travelled already 200 kms
SO speed=dist/time
time=200/220=0.9
to convert this ,
if 1 hr = 60 mins
then 0.9 hr=???
0.9*60=54 mins
T=54 mins
Adding time from 8AM gives 8:54 AM is reqd answer
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