A car leaves point A for point B every 10 minutes. The distance between A and B is 60km. The cares travel at a speed of 60kmph. Find the number of cars that a man driving from B to A at 60kmph will meet enroute (not at B or A ) if he starts from B Simultaneously with one of the cars leaBing A.
Answers
Answer:
The answer should be 6 cars.
Explanation:
I will not do the complicated mathematics to explain it but a general explaination must be sufficient to understand the problem. Lets start. We know the distance between A and B is 60 km, and cars leaves both points in every 10 minutes, this tells that in hour our 6 cars will leave A and B. Now, the car starts from B to A travels with 60 km/h it means that it will travel AB in 1 hour. From above we know that 6 cars leaves A and B in one hours. So in this way 6 cars must meet to the driver of another car starting from B to A. If you have any doubt about the explaination please comment and if you see another answer of this problem plz comment this also. If you find this answer appropriate then mark it as brainliest.
GIVEN :
◆A car leaves A for B every 10 minutes.
◆The distance between A and B is 60km.
◆The car travel at a speed of 60kmph.
TO FIND :
Find the number of cars that a man driving from B to A at 60kmph will meet enroute.
SOLUTION :
◆From A and B,
Both car leaves simultaneously at a speed of 60kmph.
◆Each car from A and B takes 1 hour to reach B, A respectively.
◆In this one hour , that is 60 minutes , from where each 10 minutes a car leaves from A. That is , 6 cars .
◆B enroutes 6 cars from A from the time he reached A.
ANSWER :
B enroutes 6 cars from A from the time he reached A.