A car leaves point P at 1310 ( 1.10 p.m. ) hours, passing through point Q at 1358 (1.58 p.m. ) hours and finally reaches point R at 1540 (3.40 p.m.) hours. The average speed of the car from Q to R is 2 times the average speed from P to Q.
P to Q = 40 km
FORMULA:
average speed = total distance / total time
Calculate the average speed, in km/h of the whole journey of the car.
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Answer:
A car leaves point P at 1310 ( 1.10 p.m. ) hours, passing through point Q at 1358 (1.58 p.m. ) hours and finally reaches point R at 1540 (3.40 p.m.) hours. The average speed of the car from Q to R is 2 times the average speed from P to Q.
P to Q = 40 km
FORMULA:
average speed = total distance / total time
Calculate the average speed, in km/h of the whole journey of the car.
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A car leaves point P at 1310 ( 1.10 p.m. ) hours, passing through point Q at 1358 (1.58 p.m. ) hours and finally reaches point R at 1540 (3.40 p.m.) hours. The average speed of the car from Q to R is 2 times the average speed from P to Q.
P to Q = 40 km
FORMULA:
average speed = total distance / total time
Calculate the average speed, in km/h of the whole journey of the car.
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