A car left 30 minutes later than the scheduled time in order to reach its destination 150km away in time it has to increase its speed by 25km/hr from its usual speed. Find its usual speed
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Answer:
Step-by-step explanation:
Let the usual speed of the car be X km/hr
Distance travelled =150km.
Time taken to travel (t¹)= 150/X
Also,
The speed increased = X +25 km/hr
So, time taken = (t²)=150/X + 25
Now,
According to the question ,we have,
t¹ - t² =30/60
150/X - 150/X + 25 = 1/2
150( X +25) - 150(X) / X(X+25)= 1/2
150X+3750 -150 X/ X² + 25X= 1/2
3750/X² + 25X= 1/2
2(3750) = 1(X² + 25X)
7500 = X² + 25X
X² + 25X - 7500=0
X² + 100X - 75 X- 7500=0
X (X + 100) -75( X +100)
(X+ 100)(X -75)
So, X = -100(speed can't be negative
.hence neglected)
or
X = 75
So , usual Speed = 75 km/hr
Hope it helps.
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