A car makes a circular turn of radius 50 m at 40 m/s. At what angle should the road be banked so that no friction is required?
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So that's the inverse tangent of 105 kilometers per hour converted into meters per second and then square that, and divide by 1.2 kilometers converted into meters, times 9.8 meters per second squared. This all gives 4.14 degrees is the ideal banking angle for this particular speed and this radius of curvature.
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