Question

A car , mass 1485 kg travelled sonth at 116 km/h slows to stop in 10.25 s , what is the magnitude and direction of the net force that actual on the car

Answer 1

Answer:

The magnitude of the force = 4603.5

The direction of the force will be to the north.

Explanation:

Mass of the car, m = 1485 Kg

The initial velocity of the car, u = 116 Km/h = 32.2 m/s

The final final of the car if it stops, v = 0 m/s

Time taken to stop the car, t = 10.25 s

From the first equation of motion, we can find the acceleration of the car.

   v = u + at

⇒ a = (v - u) / t

      = (0 - 32.2) / 10.25

   a = -3.1 m/s²

The force acting on the car, F = ma

                                                 = 1485 × -3.1

                                                 = -4603.5 N

The negative sign indicates that the force is acting opposite to the direction of the motion of the car. So the direction of the force will be towards the north and its magnitude is 4603.5.