a car masses 150 kgcomes to rest on applying brakes for 5 seconds . the force applied by the brakes is 95N .what was the intial velocity of the car
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Answer:
Velocity of moving vehicle=v
0
and decceleration =a
Final velocity of the vehicale =0 (As it stops)
Let the stopping distance be s
Then applying the third equation of motion we have:
v
2
=v
0
2
+2(−a)s
⇒0=v
0
2
−2as
⇒s=
2a
v
0
2
→ Expression for stopping distance.
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