A car meets with an accident while going to its destination and moves at ⅖ of its actual speed. Also, due to accident, it is late by 60 minutes. Find the actual time taken by the car to reach its destination? Short method
Answers
Answered by
1
let speed be s, distance be d and time be t
so s=d/t .. .. so d=s*t
but after accident 2/5*s = d * (t+60)
so d = 2/5*s * (t+60)
equating d's , you get
s*t = 2/5 * s * (t+60)
5*s*t = 2*s*t + 120 s
so... 3t = 120 , t=40
Answered by
0
Here is Ur ans don't forget to like!
Attachments:
Similar questions