Question

A car meets with an accident while going to its destination and moves at ⅖ of its actual speed. Also, due to accident, it is late by 60 minutes. Find the actual time taken by the car to reach its destination? Short method

Answer 1

let speed be s, distance be d and time be t

so s=d/t .. ..  so d=s*t

but after accident 2/5*s = d * (t+60)

so d = 2/5*s * (t+60)

equating d's , you get

s*t = 2/5 * s * (t+60)

5*s*t = 2*s*t + 120 s

so...  3t = 120 , t=40

Answer 2

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