Question

a car move with velocity 200m/s if it's velocity decrease with acceleration 2 m/s² then after 10 sec find its velocity​
ANSWER ME
PLEASE

Answer 1

Answer:

220m/s

Step-by-step explanation:

Given

u=initial velocity=200m/s

a=acceleration=2m/s^2

t=time=10sec

v=?

By third equation of motion

v=u+at

v=200+2*10 (by bodmas)

=200+20

v=220m/s

hope it helps u

Answer 2

★ AnswEr:-

$\underline{ \boxed{ \sf{ \pink{Final \: velocity = 220 \: m/s}}}}$

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★ GivEn :-

• A car moves with velocity 200m/s.
• It's velocity decrease with acceleration of 2 m/s²
• Time taken : 10 sec.

★ To Find :-

• Final velocity

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★ Solution :-

For this, we have to apply the 1st equation of motion.

The equation is :-

$\implies \underline{ \boxed{ \sf{ \pink{v = u + at}}}}$

Where,

v = final velocity of the car

u = initial velocity of the car

a = acceleration

t = time taken

Now, putting the given values, we get,

$\implies \underline{ \boxed{ \sf{ \pink{v = (200 + 2 \times 10) \: m/s}}}}$

$\implies \underline{ \boxed{ \sf{ \pink{v = (200 + 20) \: m/s}}}}$

$\implies \underline{ \boxed{ \sf{ \pink{ \therefore \: v = 220 \: m/s}}}}$

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★ The 1st equation v = u + at is used to find out the velocity acquired by a body in time 't', the body having an initial velocity 'u' and a uniform acceleration 'a'.