a car moves 4 km due east and then 3km due north. calculate the distance traveled and displacement of the car
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Answered by
9
5 km
using paythagores theorem
4^2+3^2=d^2
d=5
displacement is the shortest distance cover by body from initial to final path
Answered by
6
the car travelled to east= 4km
the car travelled to north= 3km
total distance travelled = 4km + 3km
= 7km
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