Question

A car moves 40 m due to East and turn towards north and moves 30 m then turns 45° east of North and moves 20√2 m. The net displacement
of car is?
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Answer 1

The net displacement required is AD

BF = CE = 20 root2 Cos 45 = 20m

AF = 40 + 20 = 60m

ED = 20 root2 Sin45 = 20m

DF = DE + EF = 20 + 30 = 50m

Using triangle ADF and Pythagora’s Theorem

AD = root AF 2 + DF2

 = root 60^2 + 50^2

 = 78.10m

Tan DAF = 50/60 = 5/6

< DAF = 40 Degrees

90 – 40 = 50 degrees

The net displacement = 78.10m, 50 Degrees East