Question

a car moves 5m/s to 10m/s in 5 seconds. calculate the acceleration and distance covered.​

Answer 1

Answer:

Given :

• u = 5 m/s
• v = 10 m/s
• t = 5 s

We need to find :

• Acceleration (a)
• Distance travelled

Let's use the equations of motion.

First equation : v = u + at

⇒ 10 = 5 + a*5

⇒ 10 - 5 = 5*a

⇒ 5 = 5a

⇒ a = 1 m/s²

Using the second equation : s = ut + ½at²

⇒ s = 5*5 + ½*1*5²

⇒ s = 25 + 25/2

⇒ s = (50 + 25)/2

⇒ s = 75/2

⇒ s = 37.5 m

Hence, the acceleration of the car = 1 m/s² and the distance travelled = 37.5 m.

More important formula related to rectilinear motion -

• v = u + at
• s = ut + ½at²
• v² - u² = 2as
• Avg. velocity = ∆x/∆t
• v = lim (∆t ➜ 0) ∆x/∆t = dx/dt
• Avg. acceleration = ∆v/∆t
• a = lim (∆t ➜ 0) ∆v/∆t = dv/dt
• ∆x = x_2 - x_1