Question

A car moves 8 km towards north then 6km towards east . find the distance and displacement.​

Answer 1

SOLUTION :-

Distance covered by the car = 8km + 6km

= 14km

__________________

displacement covered = √[(8)²+(6)²]

= √64+36

= √100

= 10km

Answer 2

Answer:

Distance = 14km

Displacement = 10km

Step-by-step explanation:

Given,

A car moves 8 km towards north then 6km towards east

To find,

The distance and displacement.​

Recall the concepts

Distance is the actual movement of the object without considering the direction.

Displacement is the shortest distance between the initial and final point

Solution:

Let A be the starting position of the car.

After traveling 8km towards the north, let it reaches the point B

and again traveling 6km towards the east it reaches the point C

Distance = Total distance traveled by car

= Distance between A and B + Distance between B and C

= 8+6

= 14km

Distance  = 14km

Displacement is the short distance between the initial point A to the final point C = AC

AC is the hypotenuse of the triangle ABC

By Pythagoras theorem,

AC = $\sqrt{8^2+ 6^2 } = \sqrt{64+36}$

=$\sqrt{100}$

=10Km

AC = 10km

∴Distance = 14km

Displacement = 10km

#SPJ2