. A car moves a distance of 200 km. It covers the first half of distance at a speed of 60 km/h and the second half at a speed of v km/h. If the average speed for the entire trip is 40 km/h, find the value of v
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1
Answer:
48km/h is the correct answer
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2
Answer:
First half of distance = 100m
speed = 40km/h or 100/9 m/s
so time taken= 100÷ 100/9 = 9 second
Given avg speed = 48km/h = 40/3 m/s
Distance= 200m
so total time is 15s
now 9 s has passes covering 100 m. time left = 6s
Distance left = 100m
so speed(v) = 100/6
= 50/3 m/s or 90 km/h
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