Question

a car moves along a straight line equation of motion is given by x is equal to 2t**3,+5t**2-12t where X is in meter and t is in seconds. the velocity of the car at the start will be
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Answer 1

Answer:

solved

Explanation:

x = 2t³ +5t²-12t

v = 6t² + 10t-12

at the start t = 0 , v = -12 m/s