Question

A car moves along a straight line whose equation of motion is given by S=12t+3t^2-2t^3 where s is in metres and t is in seconds.The velocity of the car at start will be?

Answer 1

Here is the answer hope this help you

Answer 2

GIVEN:

• S= 12t +3t^2-2t^3

SOLUTION:

VELOCITY= DISPLACEMENT / TIME

$= > v = \frac{ds}{dt} \\ \\ = > v = \frac{d(12t + 3t {}^{2} - 2t {}^{3} ) }{dx} \\ \\ = > v = 12 + 6t - 6t {}^{2} \\ \\ = > v = 12 \frac{m}{s} \: \: \: \: \: \: (at \: time \: = 0)$

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