Math, asked by 12546165, 4 months ago

A car moves at a constant speed of 50 miles per hour. How many hours does it take the car to go 200 miles?


Anonymous: hello

Answers

Answered by crystalroot25
5

Answer:

4 hours

Step-by-step explanation:

if it goes 50 a hour and you need to go 200 then take 200 and divide by 50 and you get 4

Answered by Anonymous
43

Given : The distance covered by the car at a constant speed of 50 miles per hour

To find : Time taken by the car to cover 200 miles

Distance covered by car in 1 hour = 50 miles per hour

Time taken to cover 200 miles

\text{new time taken} = \frac{new \:distance}{old\:distance}}\times \textsf{time taken to complete old distance}

=\frac{200}{50} \times 1

= 4 \times 1

=\boxed{\textsf{4}}}

Time taken to cover 200 miles = 4 hours

EXTRA INFORMATION

\boxed{\boxed{\textbf{DISTANCE :-}}}}

⇾Distance is the total path covered by a body in a unit time.

⇨Let's learn a few points about Distance-

•Distance is a scalar quantity.It only has magnitude, no direction , thats why it's a scalar quantity.

•Distance is always taken positive.

•Distance can never have a magnitude which is less than displacement.

\boxed{\boxed{\textbf{DISPLACEMENT :-}}}}

⇒While an object is in motion, to covers some distance.

⇒ Distance is the length of actual path covered by an object in motion.

⇒ The point from where it starts is the starting point of the body.

⇒ The place where it comes to rest is the end point.

⇒ Thus, Displacement is defined as follows:

⇴The shortest distance between the start and end points of an object in motion is defined as displacement.

⇴Displacement is always in a straight line; hence, it requires some direction to define itself.

⇴It also requires some magnitude (eg. 2km, 3km, 4km etc.) to define how much displacement occurred in which direction.

⇴ Thus, Displacement is a vector quantity as it requires both magnitude and direction to define itself.

⇻Since it is a vector quantity, it may be positive, negative or zero (if there is no motion of the body or the starting and ending points are the same).


Anonymous: Hi Roshan Bro
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