A car moves at a constant speed on a road as shown in the figure (7-Q2).The normal force by the road on the car is NA and NB when it is at the points A and B respectively.
(a) NA = NB (b) NA > NB (c) NA < NB (d) Insufficient information to decide the relation of NA and NB
Answers
Answer ⇒ Option (c). NA < NB
Explanation/Reason ⇒ Since, the car is moving at the constant speed on the road, the angular velocity of the car will be constant. Thus, On both the Positions A and B it will be constant. But, We can see that at point A, the Radius is larger as compared to B, therefore, the Centripetal Force which will balance the Car. But this Force will be larger at the Point B since, The Radius of the Point is small.
Centripetal Force = mv²/r , this means that Force is inversely proportional to the radius and if radius will decrease the Force will Increases and Vice versa.
Thus, On Point B this Force will be Larger as a result Normal Reaction will balance it and on point B it will be smaller and the Normal Reaction of there will balance it.
∴ Normal Reaction at Point A is less than at Point B.
∴ NA < NB
Hope it helps.
Answer:
Explained
As we see in the figure the normal is the force which manages the car.
So and the radius of the circle of point A is more than B. So
The equation N+MV(SQ)/R=MG.
GIVING N=MG-MV(SQ)/R.
In which the value of B>A(of normal).
Thank you.