a car moves at a speed of 4 metre per second along a horizontal road to overtake a stationary truck when it is 6 metre behind the truck the truck starts moving with a constant acceleration of 1.2 metre per second square then the time taken by the car to over take the truck is
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(a)After t sec the truck moved
s=ut+21at2
Initial velocityu=0
60=21×2.20×t2
t2=54.54
t=7.39 sec
(b) Let the distance be d meters
When they met, automobile moved
60+d=21×3.50×t2
60+d=21×3.50×7.392
60+d=95.57
d=95.57−60
d=35.57 m
(c)Velocity of truck
vT=u+at
vT=2.20×7.39=16.258 m/s
Velocity of automobile
vA=u+at
vA=3.50×7.39=25.865 m/s
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