Question

A car moves at a speed of 40 km/h. It is stopped by applying brake which produces a
uniform acceleration of -0.5 m/s2. How much distance will the vehicle move before
coming to stop?​

Answer 1

Answer:

Correct option is

A

12 m

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m