A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be joules. The braking distance at the faster speed is the braking distance at the slower speed.
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Answer:A car moving with a speed of 50 km h^-1 can be stopped by brakes after atleast 6 m. If the same car is moving at a speed of 100 km h^-1 the minimum ...
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Given, u = 50km/hr = 50 × 518 = 25018m/s v = 0 s = 6m (at least) By third equation by motion, v^2 = u^2 +
Explanation:
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