Question

A car moves at a speed of 54km/h is stopped in 2.5 sec by applying brakes . Calculate the retardation produced
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Answer 1

u = 54km/hr = 54× 5/18 = 15m/s

t = 2.5s

v = 0

by,

v = u+at

0 = 15+2.5a

-15 = 2.5a

=> -6 = a

Therefore retardation is 6m/s²,

Cheers!

Answer 2

Explanation:

ANSWER_______✍️

• u = 54km/hr = 54× 5/18 = 15m/s
• t = 2.5s
• v = 0

by,

v = u+at

• 0 = 15+2.5a
• -15 = 2.5a
• -6 = a

So the retardation is 6m/s²,

hope this helps you